Problemas con winlinux
Publicado por Alex (15 intervenciones) el 13/07/2001 17:30:15
Tengo problemas al arrancar wilinux me sale esto en la pantalla:
LOADLIN v1.6a (C) 1994..1996 Hans Lermen [email protected]>
CPU is in V86-mode (may be WINDOWS, EMM386, QEMM, 386MAX, ...)
You need pure 386/486 real mode or a VCPI server to boot Linux
VCPI is supported by most EMS drivers (if EMS is enabled),
but never under WINDOWS-3.1 or WINDOWS'95.
(However, real DOS-Mode of WINDOWS'95 can have EMS driver with VCPI)
If loading via VCPI you also MUST have:
1. An interceptable setup-code (see MANUAL.TXT)
2. Identical Physical-to-Virtual mapping for the first 640 Kbytes
Your current DOS/CPU configuration is:
load buffer size: 0x00000000 , setup buffer size: 0x3E00
total memory: 0x00100000
CPU is in V86 mode
SetupIntercept: NO
stat2: cpu_V86, but no VCPI available (check aborted)
input params (size 0x001F):
C:\Linux\vmlinuz root=/dev/hda1
LOADLIN started from DOS-prompt
You are running under MS-WINDOWS or Windows 95
WARNING: Not enough free memory (load buffer size)
mi compu es una pentium III de 1GHz
LOADLIN v1.6a (C) 1994..1996 Hans Lermen [email protected]>
CPU is in V86-mode (may be WINDOWS, EMM386, QEMM, 386MAX, ...)
You need pure 386/486 real mode or a VCPI server to boot Linux
VCPI is supported by most EMS drivers (if EMS is enabled),
but never under WINDOWS-3.1 or WINDOWS'95.
(However, real DOS-Mode of WINDOWS'95 can have EMS driver with VCPI)
If loading via VCPI you also MUST have:
1. An interceptable setup-code (see MANUAL.TXT)
2. Identical Physical-to-Virtual mapping for the first 640 Kbytes
Your current DOS/CPU configuration is:
load buffer size: 0x00000000 , setup buffer size: 0x3E00
total memory: 0x00100000
CPU is in V86 mode
SetupIntercept: NO
stat2: cpu_V86, but no VCPI available (check aborted)
input params (size 0x001F):
C:\Linux\vmlinuz root=/dev/hda1
LOADLIN started from DOS-prompt
You are running under MS-WINDOWS or Windows 95
WARNING: Not enough free memory (load buffer size)
mi compu es una pentium III de 1GHz
Valora esta pregunta


0