Java - Ordenar agrreglo de "String" segun el numero de letras

String arreglo[]={"hola","perro","sol"};

            for (int i=0; i < arreglo.length-1; i++ ) {

for (int j=i+1; j<arreglo.length; j++) {

if (arreglo[i].length() > arreglo[j].length()) {

String temp = arreglo[i];

arreglo[i] = arreglo[j];

arreglo[j] = temp;

}

}

}

 for (int i=0; i < arreglo.length; i++ ) {

     System.out.println(arreglo[i]);

     System.out.println();

 }

String[] strs = {"hola","perro","sol"};

    	Arrays.sort(strs, new Comparator<String>( ){

			public int compare(String arg0, String arg1)  {

				int larg0 = arg0.length();

				int larg1 = arg1.length();

				return larg0 < larg1 ? -1 : larg0 > larg1 ? 1 : 0;

			}});

    	for(String s : strs)  {

    		System.out.println(s);

    	}